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Sahay Sir > Question Answers > JEE Mains Physics 2002-2019 Solved Video Solutions > Practice Set 1 > For changing the capacitance of a given parallel plate capacitor, a dielectric material of dielectric constant K is used, which has the same area as the plates of the capacitor. The thickness of the dielectric slab is 3/4 d, where ‘d’ is the separation between the plates of parallel plate capacitor. The new capacitance (C’) in terms of original capacitance (C0 ) is given by the following relation :

For changing the capacitance of a given parallel plate capacitor, a dielectric material of dielectric constant K is used, which has the same area as the plates of the capacitor. The thickness of the dielectric slab is 3/4 d, where ‘d’ is the separation between the plates of parallel plate capacitor. The new capacitance (C’) in terms of original capacitance (C0 ) is given by the following relation :

a dielectric material of dielectric constant K is used For changing the capacitance of a given parallel plate capacitor where 'd' is the separation between the plates of parallel plate capacitor. The new capacitance (C') in terms of original capacitance (C0 ) is given by the following relation : which has the same area as the plates of the capacitor. The thickness of the dielectric slab is 3/4 d