Find out the value of Kc for each of the following equilibria from the value of Kp (a)2NOCl(g)⇔2NO(g)+Cl2(g),Kp=1⋅8×10−2 at 500 K (b) CaCO3(s)⇔CaO(s) ⇔ CaO(s) + CO2(g), Kp=167at1073K. Find out the value of Kc for each of the following equilibria from the value of Kp (a)2NOCl(g)⇔2NO(g)+Cl2(g) Kp=1⋅8×10−2 at 500 K (b) CaCO3(s)⇔CaO(s) ⇔ CaO(s) + CO2(g) Kp=167at1073K. November 22, 2020 Category: Chapter 7 - Equilibrium , Chemistry , NCERT Exemplar Class 11 , Facebook Messenger WhatsApp Share this:TwitterFacebook Related