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Sahay Sir > Question Answers > Cengage JEE Mains Physics by B.M Sharma > Chapter 5 - Newton's Laws of Motion (Without Friction) > Figure, represents a light inextensible string ABCDE in which AB=BC=CD=DE and to which are attached masses M, m, and M at the point B,C and D, respectively. The system hangs freely in equilibrium with ends A and E of the string fixed in the same horizontal line. it is given that tanα=3/4 and tanβ=12/5. Then the tension in the string BC is

Figure, represents a light inextensible string ABCDE in which AB=BC=CD=DE and to which are attached masses M, m, and M at the point B,C and D, respectively. The system hangs freely in equilibrium with ends A and E of the string fixed in the same horizontal line. it is given that tanα=3/4 and tanβ=12/5. Then the tension in the string BC is

and M at the point B C and D Figure m represents a light inextensible string ABCDE in which AB=BC=CD=DE and to which are attached masses M respectively. The system hangs freely in equilibrium with ends A and E of the string fixed in the same horizontal line. it is given that tanα=3/4 and tanβ=12/5. Then the tension in the string BC is