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Sahay Sir > Question Answers > NCERT Exemplar Class 12 > Maths > Chapter 11 - 3D Geometry > Example 13 Find the vector equation of the plane which is at a distance of 6/sqrt 29 from the origin and its normal vector from the origin is 2i – 3j + 4k.

Example 13 Find the vector equation of the plane which is at a distance of 6/sqrt 29 from the origin and its normal vector from the origin is 2i – 3j + 4k.

Example 13 Find the vector equation of the plane which is at a distance of 6/sqrt 29 from the origin and its normal vector from the origin is 2i - 3j + 4k.