Sahay Sir > Question Answers > NEET Last 32 Years Solved 1988 - 2019 Physics and Chemistry Video Solutions > Physics > Chapter 30 - Atoms > Energy E of a hydrogen atom with principle quantum number n is given by E=−13.6n2eV. The energy of a photon ejected when the electron jumps from n=3 state to n=2 state of hydrogen is approximately

Energy E of a hydrogen atom with principle quantum number n is given by E=−13.6n2eV. The energy of a photon ejected when the electron jumps from n=3 state to n=2 state of hydrogen is approximately

Energy E of a hydrogen atom with principle quantum number n is given by E=−13.6n2eV. The energy of a photon ejected when the electron jumps from n=3 state to n=2 state of hydrogen is approximately