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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > During the Kolbe’s electrolytic decarboxylation of CH3COONa (a) H2 is liberated at cathode because discharge potential of H+ is less than discharge potential of Na+

During the Kolbe’s electrolytic decarboxylation of CH3COONa (a) H2 is liberated at cathode because discharge potential of H+ is less than discharge potential of Na+

During the Kolbe's electrolytic decarboxylation of CH3COONa (a) H2 is liberated at cathode because discharge potential of H+ is less than discharge potential of Na+