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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > Consider one of fission reaction of 235U by thermal neutrons 235U92 + n gives 94Sr38 + 140Xe54 + 2n. The fission fragments are however unstable and they undergo successive beta decay until 94Sr38 becomes 94Zr40

Consider one of fission reaction of 235U by thermal neutrons 235U92 + n gives 94Sr38 + 140Xe54 + 2n. The fission fragments are however unstable and they undergo successive beta decay until 94Sr38 becomes 94Zr40

1.00 kg of 235 U undergoes fission process. If energy released per event is 200 MeV then the total energy released is