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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > Conc. H2SO4 heated with excess of C2H5OH at 140 C to form (a) CH3CH2 – O – CH3 (b) CH3CH2 -O- CH2CH3 (c) CH3 -O- CH2 – CH2 – CH3 (d) CH2 = CH2

Conc. H2SO4 heated with excess of C2H5OH at 140 C to form (a) CH3CH2 – O – CH3 (b) CH3CH2 -O- CH2CH3 (c) CH3 -O- CH2 – CH2 – CH3 (d) CH2 = CH2

Conc. H2SO4 heated with excess of C2H5OH at 140 C to form (a) CH3CH2 - o - CH3 (b) CH3CH2 -O- CH2CH3 (c) CH3 -O- CH2 - CH2 - CH3 (d) CH2 = CH2