Choose the correct option Two seconds after the projection, a projectile is moving at 30∘ above the horizontal, after one more second it moves horizontally (g=10 m/s 2).

Two seconds after projection, a projectile is travelling in a direction inclined at 30 to the horizontal. After one more second, it is travelling horizontally. Find the magnitude and direction of its velocity.

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The trajectory of a projectile in a vertical plane is y=ax−bx^2, where a,b are constants and x and y are, respectively, horizontal and vertical distances of the projectile from the point of projection. The maximum height attained by the particle and the angle of projectile from the horizontal are.

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The trajectory of a projectile in a vertical plane is y=αx−βx^2 where α and β are constants and x and y are respectively the horizontal and vertical distances of the projectile from the point of projection. The angle of projection theta and the maximum height attended H are respectively given by: