B . P . of H2O (100 degree C ) and H2S ( -42 degree C ) is explained by (a) Vander waal’s forces (b) Covalent bond (c) Hydrogen bond (d) Ionic bond B . P . of H2O (100 degree C ) and H2S ( -42 degree C ) is explained by (a) Vander waal's forces (b) Covalent bond (c) Hydrogen bond (d) Ionic bond December 9, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) , Facebook Messenger WhatsApp Share this:TwitterFacebook Related