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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > At a height 0.4 m from the ground, the velocity of a projectile in vector form is v = (6i + 2j) m/s. The angle of projection is

At a height 0.4 m from the ground, the velocity of a projectile in vector form is v = (6i + 2j) m/s. The angle of projection is

At a height 0.4 m from the ground the velocity of a projectile in vector form is v = (6i + 2j) m/s. The angle of projection is