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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > As a result of the isobaric heating by delta T = 72 K, one mole of a certain ideal gas receives heat Q = 1.6 kJ. Find the work performed by the gas, the increment of its internal energy,

As a result of the isobaric heating by delta T = 72 K, one mole of a certain ideal gas receives heat Q = 1.6 kJ. Find the work performed by the gas, the increment of its internal energy,

As a result of the isobaric heating by delta T = 72 K one mole of a certain ideal gas receives heat Q = 1.6 kJ. Find the work performed by the gas the increment of its internal energy