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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > Analyze the given circuit in the steady state condition. Charge on the capacitor is q0 =16μC Analyze the given circuit in the steady state condition. Charge on the capacitor isq0=16μCAnalyze the given circuit in the steady state condition. Charge on the capacitor isq0=16μC (a) Find the current in each branch (b) Find the emf of the battery. (c) If now the battery is removed and the points A and C are shorted. Find the time during which charge on the capacitor becomes 5.92 muC.

Analyze the given circuit in the steady state condition. Charge on the capacitor is q0 =16μC Analyze the given circuit in the steady state condition. Charge on the capacitor isq0=16μCAnalyze the given circuit in the steady state condition. Charge on the capacitor isq0=16μC (a) Find the current in each branch (b) Find the emf of the battery. (c) If now the battery is removed and the points A and C are shorted. Find the time during which charge on the capacitor becomes 5.92 muC.

all batteries have emf 10 V and internal resistance negligible. All the resistors are in ohm. Calculate the current in the rightmost 2ohm resistor. In the given circuit in figure