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Sahay Sir > Question Answers > JEE Mains Physics 2002-2019 Solved Video Solutions > Chapter 18 - Atoms and Nuclei > An α-particle of energy 5 MeV is scattered through 180^∘ by a fixed uranium nucleus. The distance of the closest approach is of the order of

An α-particle of energy 5 MeV is scattered through 180^∘ by a fixed uranium nucleus. The distance of the closest approach is of the order of

An α-particle of energy 5 MeV is scattered through 180^∘ by a fixed uranium nucleus. The distance of the closest approach is of the order of