An object, moving with a speed of 6.25 m/s, is decelerated at a rate given by: dt/dv = − 2.5v where v is the instantaneous speed. The time taken by the object, to come to rest, would be: An object is decelerated at a rate given by: dt/dv = − 2.5v where v is the instantaneous speed. The time taken by the object moving with a speed of 6.25 m/s to come to rest would be September 10, 2020 Category: Chapter 3 - Motion in One Dimension , MTG NEET Physics , Part 1 , Facebook Messenger WhatsApp Share this:TwitterFacebook Related