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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > An inductor coil stores 32 J of magnetic field energy and dissipates energy as heat at the rate of 320 W when a current of 4 A is passed through it . Find the time constant of the circuit when it is formed across an ideal battery.

An inductor coil stores 32 J of magnetic field energy and dissipates energy as heat at the rate of 320 W when a current of 4 A is passed through it . Find the time constant of the circuit when it is formed across an ideal battery.

(assume that the internal resistance of the battery and of the connecting wire are negligible) In the circuit shown in fig the time constant of the two braches are equal(=T). Then if the key S is closed at the instant t=0 the time in which the current in the circuit through the battery will rise to its final value of (E/R) will be