An electron moves through a uniform magnetic field given by B = Bxiˆ+(3Bx) jˆ. At a particular instant, the electron has the velocity v = ( 2.0iˆ+4.0jˆ) m/s and the magnetic force acting on its is ( 6.4×10^−19 N ) kˆ Find Bx. An electron moves through a uniform magnetic field given by B = Bxiˆ+(3Bx) jˆ. At a particular instant the electron has the velocity v = ( 2.0iˆ+4.0jˆ) m/s and the magnetic force acting on its is ( 6.4×10^−19 N ) kˆ Find Bx. October 13, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) , Facebook Messenger WhatsApp Share this:TwitterFacebook Related