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Sahay Sir > Question Answers > NEET Last 32 Years Solved 1988 - 2019 Physics and Chemistry Video Solutions > Physics > Chapter 29 - Dual Nature of Matter and Radiation > An electron is accelerated through a potential difference of 10,000 V. Its de-Broglie wavelength is, (nearly): (me, = 9 × 10^ − 31kg)

An electron is accelerated through a potential difference of 10,000 V. Its de-Broglie wavelength is, (nearly): (me, = 9 × 10^ − 31kg)

(nearly): (me =9×10^−31kg) 000V. Its de-Broglie wavelength is An electron is accelerated through a potential difference of 10