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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > An electron accelerated by a potential difference V=3 volt first enters into a uniform electric field of a parallel plate capacitor whose plates extend over a length l=6cm in the direction of initial velocity. The electric field is normal to the direction of initial velocity and its strength varies with time as E=αt, where α=3600Vm^−1s^−1. Then the electron enters into a uniform magnetic field of induction

An electron accelerated by a potential difference V=3 volt first enters into a uniform electric field of a parallel plate capacitor whose plates extend over a length l=6cm in the direction of initial velocity. The electric field is normal to the direction of initial velocity and its strength varies with time as E=αt, where α=3600Vm^−1s^−1. Then the electron enters into a uniform magnetic field of induction

A loop of flexible conducting wire of length 0.5 m lies in a magnetic field of 1.0 T perpendicular to the plane of the loop. Show that when a current as shown in Fig. 1.112 is passed through the loop it opens into a circle. Also calculate the tension developed in the wire if the current is 1.57 A.