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Sahay Sir > Question Answers > JEE Mains Physics 2002-2019 Solved Video Solutions > Practice Set 1 > An electric field vector E = 4xi – (y^2 + 1)jN/C passes through the box shown in figure. The flux of the electric field through surfaces ABCD and BCGF are marked as ϕI and ϕII respectively. The difference between (ϕI – ϕII) is (in Nm^2/C) ___________.

An electric field vector E = 4xi – (y^2 + 1)jN/C passes through the box shown in figure. The flux of the electric field through surfaces ABCD and BCGF are marked as ϕI and ϕII respectively. The difference between (ϕI – ϕII) is (in Nm^2/C) ___________.

Which of the following gives a reversible operation?