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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > An electric field given by E = 4.0i -3.0 (y^2 +2.0 ) j pierces a Gaussian cube of edgr length 2 m and positioned as shown in the figure. ( The magnitude E is in newtons per coulomb and the position x is in meters.) What is the electric flux through the (a) top face, (b) what is the net electric flux through the cube ?

An electric field given by E = 4.0i -3.0 (y^2 +2.0 ) j pierces a Gaussian cube of edgr length 2 m and positioned as shown in the figure. ( The magnitude E is in newtons per coulomb and the position x is in meters.) What is the electric flux through the (a) top face, (b) what is the net electric flux through the cube ?

0 ) and ( 1m 0) is 2 m ) respectively. The resultant electric field due to the two dipoles at the point (1 m Two short dipoles pk and p/2 k are located at ( 0