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Sahay Sir > Question Answers > JEE Mains Physics 2002-2019 Solved Video Solutions > Practice Set 1 > An electric dipole of moment vector p = (-i – 3j + 2k) x 10^-29 C. m is at the origin (0, 0, 0). The electric field due to this dipole at vector r = i + 3j + 5k (note that vector(r.p) = 0) is parallel to:

An electric dipole of moment vector p = (-i – 3j + 2k) x 10^-29 C. m is at the origin (0, 0, 0). The electric field due to this dipole at vector r = i + 3j + 5k (note that vector(r.p) = 0) is parallel to:

0). The electric field due to this dipole at vector r = i + 3j + 5k (note that vector(r.p) = 0) is parallel to: An electric dipole of moment vector p = (-i - 3j + 2k) x 10^-29 C. m is at the origin (0