An electric dipole is placed at an angle of 30∘ with an electric field of intensity 2×10^5 NC^−1. It experiences a torque equal to 9Nm. Calculate the charge on the dipole if the dipole length is 2cm is Force between two identical charges placed at a distance of r in vacuum is F. Now a slab of dielectric constant K = 4 is inserted between these two charges . If the thickness of the slab is r/2 then the force between the charges will becomes November 30, 2020 Category: Cengage JEE Mains Physics by B.M Sharma , Chapter 17 - Electric Charge and Field , Facebook Messenger WhatsApp Share this:TwitterFacebook Related