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Sahay Sir > Question Answers > JEE Mains Physics 2002-2019 Solved Video Solutions > Practice Set 1 > An aeroplane, with its wings spread 10 m, is flying at a speed of 180 km/h in a horizontal direction. The total intensity of earth’s field at that part is 2.5 × 10^–4 Wb/m^2 and the angle of dip is 60°. The emf induced between the tips of the plane wings will be :-

An aeroplane, with its wings spread 10 m, is flying at a speed of 180 km/h in a horizontal direction. The total intensity of earth’s field at that part is 2.5 × 10^–4 Wb/m^2 and the angle of dip is 60°. The emf induced between the tips of the plane wings will be :-

An aeroplane The logic circuit shown above is equivalent to : with its wings spread 10 m