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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > An adiabatic vessel contains n1 = 3 mole of diatomic gas. Moment of inertia of each molecule is I=2.76×10^−46kgm^2 and root-mean-square angular velocity is ω0=5×10^12rad/s. Another adiabatic vessel contains n2=5 mole of a monoatomic gas at a temperature 470K. Assume gases to be ideal, calculate root-mean-square angular velocity of diatomic molecules when the two vessels are connected by a thin tube

An adiabatic vessel contains n1 = 3 mole of diatomic gas. Moment of inertia of each molecule is I=2.76×10^−46kgm^2 and root-mean-square angular velocity is ω0=5×10^12rad/s. Another adiabatic vessel contains n2=5 mole of a monoatomic gas at a temperature 470K. Assume gases to be ideal, calculate root-mean-square angular velocity of diatomic molecules when the two vessels are connected by a thin tube

Find the minimum attainable pressure of an ideal gas in the process T=T0+αV^2 Where T0 and α are positive constant and V is the volume of one mole of gas. Draw the approximate T−V plot of this process.