An α-particle having kinetic energy 5 MeV falls on a Cu-foil. The shortest distance from the nucleus of Cu to which α- particle reaches is (Atomic no. of Cu=29,K = 9 × 10^9Nm^2/C^2) An α-particle having kinetic energy 5 MeV falls on a Cu-foil. The shortest distance from the nucleus of Cu to which α- particle reaches is (Atomic no. of Cu=29 K = 9 × 10^9Nm^2/C^2) November 10, 2020 Category: Chapter 2 - Atomic Structure (Level 1 and Level 2) , N Awasthi Physical Chemistry , Facebook Messenger WhatsApp Share this:TwitterFacebook Related