Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A double-pane window consists of two glass sheets each of area 1m^(2) and thickness 0.01m separated by a 0.05 m thick stagnant air space. In the steady state, the room glass interface and the glass outdoor interface are at constant temperature of 27^(@)C and 0^(@)C, respectively. (a) Calculate the rate of heat flow through the window pane. (b) Find the temperatures of other interfaces. [Take: thermal conductivities as K_(glass)=0.8Wm^(-1)K^(-1) and K_(air)=0.08Wm^(-1)K^(-1)]

A double-pane window consists of two glass sheets each of area 1m^(2) and thickness 0.01m separated by a 0.05 m thick stagnant air space. In the steady state, the room glass interface and the glass outdoor interface are at constant temperature of 27^(@)C and 0^(@)C, respectively. (a) Calculate the rate of heat flow through the window pane. (b) Find the temperatures of other interfaces. [Take: thermal conductivities as K_(glass)=0.8Wm^(-1)K^(-1) and K_(air)=0.08Wm^(-1)K^(-1)]

A double-pane window consists of two glass sheets each of area 1m^(2) and thickness 0.01m separated by a 0.05 m thick stagnant air space. In the steady state Cubical expansivity of benzene =1.2xx10^(-3)K^(-1) Cubical expansivity of wood =1.5xx10^(-4)K^(-1) Density of wood at 0^(@)C=8.8xx10^(2)kgm^(-3) find the change in temperature at which wood will just sink in benzene. Density of benzene at 0^(@)C=9xx10^(2)kgm^(-3) the room glass interface and the glass outdoor interface are at constant temperature of 27^(@)C and 0^(@)C Using the following data