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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > Acetyl bromide reacts with excess of CH3MgI followed by treatment with a saturated solution of NH4Cl gives (a) 2-methyl-2-propanol (b) Acetamide (c) Acetone (d) Acetyl iodide

Acetyl bromide reacts with excess of CH3MgI followed by treatment with a saturated solution of NH4Cl gives (a) 2-methyl-2-propanol (b) Acetamide (c) Acetone (d) Acetyl iodide

Acetyl bromide reacts with excess of CH3MgI followed by treatment with a saturated solution of NH4Cl gives (a) 2-methyl-2-propanol (b) Acetamide (c) Acetone (d) Acetyl iodide