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Sahay Sir > Question Answers > NEET Last 32 Years Solved 1988 - 2019 Physics and Chemistry Video Solutions > Chemistry > Chapter 2 - Atomic Structure > According to law of photochemical equivalence the energy absorbed (in ergs/mole) is a given as (h = 6.62×10^−27 ergs , c = 3 × 10^10 cms^−1,NA = 6.02 × 10^23mol^−1)

According to law of photochemical equivalence the energy absorbed (in ergs/mole) is a given as (h = 6.62×10^−27 ergs , c = 3 × 10^10 cms^−1,NA = 6.02 × 10^23mol^−1)

According to law of photochemical equivalence the energy absorbed (in ergs/mole) is a given as (h = 6.62×10^−27 ergs c = 3 × 10^10 cms^−1 NA = 6.02 × 10^23mol^−1)