Question Answers

Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > AB is a uniform wire of length L=100 cm. A cell of emf V0 = 12 volt is connected across AB. A resistance R, cell of emf V and a milliammeter (which can show deflection in both directions] is connected to the circuit as shown. Contact C can be slid on the wire AB. Distance AC=x. The current (I) through the milliammeter is taken positive when the cell of emf V is discharging. A graph of IVsx has been shown. Neglect internal resistance of the cells. (a) Find V (b) Find R (c) find I when x=100 cm

AB is a uniform wire of length L=100 cm. A cell of emf V0 = 12 volt is connected across AB. A resistance R, cell of emf V and a milliammeter (which can show deflection in both directions] is connected to the circuit as shown. Contact C can be slid on the wire AB. Distance AC=x. The current (I) through the milliammeter is taken positive when the cell of emf V is discharging. A graph of IVsx has been shown. Neglect internal resistance of the cells. (a) Find V (b) Find R (c) find I when x=100 cm

AB is a uniform wire of length L=100 cm. A cell of emf V0 = 12 volt is connected across AB. A resistance R as shown In the circuit shown in figure AB is a uniform wire of length L = 5 m. It has a resistance of 2Ω/m. When AC=2.0 m In the circuit shown in the figure: it was found that the galvanometer shows zero reading when switch s is placed in either of the two positions 1 or 2. find the emf E1. R2=2kΩandR3=5kΩ have been connected to a constant current source as shown in figure. The current source supplies current I=2mA to the circuit. A voltmeter with RV=6kΩ internal resistance is connected Three resistors R1=3kΩ