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Sahay Sir > Question Answers > JEE Mains Physics 2002-2019 Solved Video Solutions > Practice Set 1 > A wire of density 9 × 10^–3 kg cm^–3 is stretched between two clamps 1 m apart. The resulting strain in the wire is 4.9 × 10^–4. The lowest frequency of the transverse vibrations in the wire is (Young’s modulus of wire Y = 9 x 10^10 Nm^–2), (to the nearest integer),…….

A wire of density 9 × 10^–3 kg cm^–3 is stretched between two clamps 1 m apart. The resulting strain in the wire is 4.9 × 10^–4. The lowest frequency of the transverse vibrations in the wire is (Young’s modulus of wire Y = 9 x 10^10 Nm^–2), (to the nearest integer),…….

area A and force F are chosen as fundamental units If speed (V) then the dimension of Young’s modulus will be