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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A wave is propagating on a long stretched string along its length taken as the positive x-axis. The wave equation is given as y = y0e ^ -(t/T – x/lemda)^2 where y. = 4 mm, T = 1.0 s and lemda = 4 cm. (a) Find the velocity of the wave.

A wave is propagating on a long stretched string along its length taken as the positive x-axis. The wave equation is given as y = y0e ^ -(t/T – x/lemda)^2 where y. = 4 mm, T = 1.0 s and lemda = 4 cm. (a) Find the velocity of the wave.

A wave is propagating on a long stretched string along its length taken as the positive x-axis. The wave equation is given as y = y0e ^ -(t/T - x/lemda)^2 where y. = 4 mm T = 1.0 s and lemda = 4 cm. (a) Find the velocity of the wave.