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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A uniformly wound solenoid coil of self inductance 4 mH and resistance 12 ohm is broken into two parts. These two coils are connectd in parallel across a 12 V battery . The steady current through battery is

A uniformly wound solenoid coil of self inductance 4 mH and resistance 12 ohm is broken into two parts. These two coils are connectd in parallel across a 12 V battery . The steady current through battery is

(assume that the internal resistance of the battery and of the connecting wire are negligible) In the circuit shown in fig the time constant of the two braches are equal(=T). Then if the key S is closed at the instant t=0 the time in which the current in the circuit through the battery will rise to its final value of (E/R) will be