A uniform rod of length l and mass m is free to rotate in a vertical plane about A. The rod initially in horizontal position is released. The initial angular acceleration of the rod is (Moment of inertia of rod about A is 3/ml^2.) The instantaneous angular position of a point on a rotating wheel is given by the equation Q(t)=2t^3 − 6t^2. The torque on the wheel becomes zero at : August 29, 2020 Category: Chapter 11 - Rotational Mechanics , NEET Last 32 Years Solved 1988 - 2019 Physics and Chemistry Video Solutions , Physics , Facebook Messenger WhatsApp Share this:TwitterFacebook Related