A uniform force of (3i^+j^) newton acts on a particle of mass 2 kg. Hence the particle is displaced from position (2i^+k^) meter to position (4i^+3j^−k^) meter. The work done by the force on the particle is A particle moves from a point (-2i^ + 5j^) to (4j^ + 3k^ ) when a force of (4i^+3j^) N is applied. How much work has been done by the force ? August 28, 2020 Category: Chapter 7 - Work, Energy and Power , NEET Last 32 Years Solved 1988 - 2019 Physics and Chemistry Video Solutions , Physics , Facebook Messenger WhatsApp Share this:TwitterFacebook Related