A transverse pulse moving on a long string along x-axis is given as, Y = 2/(5x – 3t)^2 + 1 , where x is measured in meter y in centimeter and t is measured in seconds. Find the (1) wave speed, height of the pulse A transverse pulse moving on a long string along x-axis is given as height of the pulse where x is measured in meter y in centimeter and t is measured in seconds. Find the (1) wave speed Y = 2/(5x - 3t)^2 + 1 September 4, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) , Facebook Messenger WhatsApp Share this:TwitterFacebook Related