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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A Thin uniform rod AB of mass m = 1.0 kg moves translationally with acceleration a = 2.0 m/s^2 due to two antiparallel forces F1 and F2. The distance between the points at which these forces are applied is equal to d = 20 cm. Besides, it is known that F2 = 5.0 N. Find the length of the rod.

A Thin uniform rod AB of mass m = 1.0 kg moves translationally with acceleration a = 2.0 m/s^2 due to two antiparallel forces F1 and F2. The distance between the points at which these forces are applied is equal to d = 20 cm. Besides, it is known that F2 = 5.0 N. Find the length of the rod.

A disc rolls on ground without slipping. Velocity of centre of mass is v. There is a point P on circumference of disc at angle θ. Suppose match the following columns vP is the speed of this point. Then