Sahay Sir > Question Answers > NEET Last 32 Years Solved 1988 - 2019 Physics and Chemistry Video Solutions > Physics > Chapter 26 - EMI > A thin semicircular conducting the ring (PQR) of radius ′r′ is falling with its plane vertical in a horizontal magnetic field B, as shown in figure. The potential difference developed across the ring when its speed is v, is

A thin semicircular conducting the ring (PQR) of radius ′r′ is falling with its plane vertical in a horizontal magnetic field B, as shown in figure. The potential difference developed across the ring when its speed is v, is

A thin semicircular conducting the ring (PQR) of radius ′r′ is falling with its plane vertical in a horizontal magnetic field B as shown in figure. The potential difference developed across the ring when its speed is v is