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Sahay Sir > Question Answers > JEE Mains Physics 2002-2019 Solved Video Solutions > Chapter 16 - Optics > A thin convex lens L (refractive index = 1.5) is placed on a plane mirror M. When a pin is placed at A, such that OA = 18 cm, its real inverted image is formed at A itself, as shown in figure. When a liquid of refractive index μ1 is put between the lens and the mirror, The pin has to be moved to A’, such that OA’ = 27 cm, to get its inverted real image at A’ itself. The value of μ1 will be

A thin convex lens L (refractive index = 1.5) is placed on a plane mirror M. When a pin is placed at A, such that OA = 18 cm, its real inverted image is formed at A itself, as shown in figure. When a liquid of refractive index μ1 is put between the lens and the mirror, The pin has to be moved to A’, such that OA’ = 27 cm, to get its inverted real image at A’ itself. The value of μ1 will be

A thin convex lens L (refractive index = 1.5) is placed on a plane mirror M. When a pin is placed at A as shown in figure. When a liquid of refractive index μ1 is put between the lens and the mirror its real inverted image is formed at A itself such that OA = 18 cm such that OA' = 27 cm The pin has to be moved to A' to get its inverted real image at A' itself. The value of μ1 will be