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Sahay Sir > Question Answers > JEE Adv and Mains Chemistry 41 Years Solved Video Solutions 1979 - 2019 > Chemistry > Chapter 2 - Atomic Structure > (a) The Schrodinger wave equation for hydrogen atom is: Ψ2s ​ = 1/ 4 (2 π)^v2 (1/a0)3/2 [2− a0/r ]e^−r/a 0 ​ where a 0 ​ is Bohr radius. If the radial node in 2s be at r0 ​ , then find r in terms of a0 . (b) A ball of 100 g mass is thrown with a velocity of 100 m/s. Find out the value of wavelength of base ball.

(a) The Schrodinger wave equation for hydrogen atom is: Ψ2s ​ = 1/ 4 (2 π)^v2 (1/a0)3/2 [2− a0/r ]e^−r/a 0 ​ where a 0 ​ is Bohr radius. If the radial node in 2s be at r0 ​ , then find r in terms of a0 . (b) A ball of 100 g mass is thrown with a velocity of 100 m/s. Find out the value of wavelength of base ball.

(a) The Schrodinger wave equation for hydrogen atom is: Ψ2s ​ = 1/ 4 (2 π)^v2 (1/a0)3/2 [2− a0/r ]e^−r/a 0 ​ where a 0 ​ is Bohr radius. If the radial node in 2s be at r0 ​ then find r in terms of a0 . (b) A ball of 100 g mass is thrown with a velocity of 100 m/s. Find out the value of wavelength of base ball.