A straight wire of mass 200 g and length 1.0 m carries a current of 2 A. It is suspended in mid-air by a uniform horizontal magnetic field B. What is the magnitude of the magnetic field ? Take g = 10 m/s ^2. (b) distance travelled in the magnetic field (c) impulse of magnetic force. A positive charge particle of charge q and mass m enters into a uniform magnetic field with velocity v as shown in Fig. There is no magnetic field to the left of PQ. Find (a) time spent Electrons in a beam are accelerated from rest through a potential difference ΔV. The beam enters an experimental chamber through a small hole. As shown in Fig. 1.35 the electron velocity vector lie within a narrow cone of half angle ϕ oriented along the beam axis. We wish to use a uniform magnetic field directed parallel to the axis to focus the beam October 13, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) , Facebook Messenger WhatsApp Share this:TwitterFacebook Related