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Sahay Sir > Question Answers > Cengage NEET by C.P Singh > Part 1 > Chapter 11 - Rotational Motion > A stone of mass m tied to the end of a string, is whirled around in a horizontal circle. (Neglect the force due to gravity). The length of the string is reduced gradually keeping the angular momentum of the stone about the centre of the circle constant. Then, the tension in the string is given by T=A r^n where A is a constant, r is the instantaneous radius of the circle and n is

A stone of mass m tied to the end of a string, is whirled around in a horizontal circle. (Neglect the force due to gravity). The length of the string is reduced gradually keeping the angular momentum of the stone about the centre of the circle constant. Then, the tension in the string is given by T=A r^n where A is a constant, r is the instantaneous radius of the circle and n is

A solid sphere is rotating about a diameter at an angular velocity ω. If it cools so that its radius reduces to I/n of its original value A stone of mass m tied to the end of a string its angular velocity becomes