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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A stick AB of mass M is tied at one end to a light string OA. A horizontal force F = Mg is applies at end B of the stick and its remains in equilibrium in position shown. Then angle ′ α ′ is.

A stick AB of mass M is tied at one end to a light string OA. A horizontal force F = Mg is applies at end B of the stick and its remains in equilibrium in position shown. Then angle ′ α ′ is.

A stick AB of mass M is tied at one end to a light string OA. A horizontal force F = Mg is applies at end B of the stick and its remains in equilibrium in position shown. Then angle ′ α ′ is.