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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A standing wave on a string is given by y = (4 cm) cos (x pie) sin (50 pie t), where x is in metres and t is in seconds. The velocity of the string section at x = 1/3 m at t = 1/5 s, is

A standing wave on a string is given by y = (4 cm) cos (x pie) sin (50 pie t), where x is in metres and t is in seconds. The velocity of the string section at x = 1/3 m at t = 1/5 s, is

A standing wave on a string is given by y = (4 cm) cos (x pie) sin (50 pie t) is where x is in metres and t is in seconds. The velocity of the string section at x = 1/3 m at t = 1/5 s