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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A square wire loop with L= 1 m sides is perpendicular to a uniform magnetic field, with half the area of the loop in the field (see Fig.). the resistance of the loop is 35 ohm and the loop contains an ideal battery with emf = 6 V . if magnitude of the field varies with time according to B = 5 – 2t , with B is testlals and t in seconds what are (a) the net emf in the circuit (b) the direction of the current around the loop.

A square wire loop with L= 1 m sides is perpendicular to a uniform magnetic field, with half the area of the loop in the field (see Fig.). the resistance of the loop is 35 ohm and the loop contains an ideal battery with emf = 6 V . if magnitude of the field varies with time according to B = 5 – 2t , with B is testlals and t in seconds what are (a) the net emf in the circuit (b) the direction of the current around the loop.

A long copper wire carries a current of I ampere. Calculate the magnetic flux per meter of the wire for a plane surface S inside the wire as shown in Fig. A square wire loop with L= 1 m sides is perpendicular to a uniform magnetic field A wire forms a closed circular loop of radius = 1 m and resistance 5 ohm . The circle is centered on a long straight wire; at time t = 0 the current in the long straight wire is 10 rightward. Thereafter