Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A conducting rod is bent as a parabola y=Kx^(2), where K is a constant and it is placed in a unifrom magnetic field of induction B. At t=0 a conductor of resistance per unit length lambda starts sliding up on the parabola with a constant acceleration a and the parabolic frame starts rotating with constant angular frequency omega about the axis of symmetry, as shown in the figure. Find the instantaneous current induced in the rod, when the frame turns through pi//4rad.

A conducting rod is bent as a parabola y=Kx^(2), where K is a constant and it is placed in a unifrom magnetic field of induction B. At t=0 a conductor of resistance per unit length lambda starts sliding up on the parabola with a constant acceleration a and the parabolic frame starts rotating with constant angular frequency omega about the axis of symmetry, as shown in the figure. Find the instantaneous current induced in the rod, when the frame turns through pi//4rad.

A conducting rod is bent as a parabola y=Kx^(2) A square loop of side 'a' with a capacitor of capacitance C is located between two current carrying long parallel wires as shown. The value of I in the wires in given as I=(I_0) sin omega t.