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Sahay Sir > Question Answers > MTG NEET Physics > Part 1 > Chapter 6 - Work, Energy and Power > A spring of constant 100N/m is stretched by applying equal forces each of magnitude F at the two ends . The energy stored in the spring is 200 J . Now , spring is cut into two equal parts and one of the part is stretched by applying equal forces each of magnitude F at the ends . The energy stored is

A spring of constant 100N/m is stretched by applying equal forces each of magnitude F at the two ends . The energy stored in the spring is 200 J . Now , spring is cut into two equal parts and one of the part is stretched by applying equal forces each of magnitude F at the ends . The energy stored is

A spring of constant 100N/m is stretched by applying equal forces each of magnitude F at the two ends . The energy stored in the spring is 200 J . Now spring is cut into two equal parts and one of the part is stretched by applying equal forces each of magnitude F at the ends . The energy stored is