A solution is 0.10M in Ba(NO3)2 and 0.10M in Sr(NO3)2. If solid Na2CrO4 is added to the solution, what is [Ba2+], when SrCrO4 beings to precipitate? [Ksp(BaCrO4)=1.2×10^−10,Ksp(SrCrO4)=3.5 × 10^−5] A solution is 0.10M in Ba(NO3)2 and 0.10M in Sr(NO3)2. If solid Na2CrO4 is added to the solution Ksp(SrCrO4)=3.5 × 10^−5] what is [Ba2+] when SrCrO4 beings to precipitate? [Ksp(BaCrO4)=1.2×10^−10 November 22, 2020 Category: Chapter 6 - Ionic Equilibrium (Level 1 and Level 2) , Chapter 7 - Equilibrium , N Awasthi Physical Chemistry , Facebook Messenger WhatsApp Share this:TwitterFacebook Related