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Sahay Sir > Question Answers > JEE Mains Physics 2002-2019 Solved Video Solutions > Practice Set 1 > A solid sphere of radius R gravitationally attracts a particle placed at 3R form its centre with a force F1. Now a spherical cavity of radius (R/2) is made in the sphere (as shown in figure) and the force becomes F2. The value of F1 : F2 is :

A solid sphere of radius R gravitationally attracts a particle placed at 3R form its centre with a force F1. Now a spherical cavity of radius (R/2) is made in the sphere (as shown in figure) and the force becomes F2. The value of F1 : F2 is :

The logic circuit shown above is equivalent to :