A solid cylinder rolls down an inclined plane of height 3 m and reaches the bottom of plane with angular velocity, of 2 2–√rads^−1 . The radius of cylinder must be (Take g = 10 ms^−2 ) A solid cylinder rolls down an inclined plane of height 3 m and reaches the bottom of plane with angular velocity of 2 2–√rads^−1 . The radius of cylinder must be (Take g = 10 ms^−2 ) November 27, 2020 Category: Cengage NEET by C.P Singh , Chapter 11 - Rotational Motion , Part 1 , Facebook Messenger WhatsApp Share this:TwitterFacebook Related